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DQL -- 子查询(Subquery)

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子查询

  • 含义:出现在其他语句中的select语句,称为子查询或者内查询
    外部的查询语句,叫做主查询或外查询

  • 分类

    • 按子查询出现的位置:
      • select语句
        只支持标量子查询
      • from语句
        支持表子查询
      • where或者having后面(重点)
        标量子查询(单行)
        列子查询(多行)
        行子查询(使用较少)
      • exists语句后面(相关子查询)
        表子查询
    • 按结果集的行列数不同
      + 标量子查询(结果只有一行一列)
      + 列子查询(只有一列多行)
      + 行子查询(结果可以有一行一列)
      + 表子查询(结果集一般为多行多列)

一、where或者having后面的子查询

  • 列子查询多行比较运算符

    1. IN/NOT IN:等于列表中的任意一个
    2. ANY/SOME:和子查询列表中的某一个比较(类似于每一个值比较都是或运算)
    3. ALL:和子查询列表中的每一个值比较(类似于每一个值比较都是与运算)
  • 特点

    1. 子查询放在小括号里面

    2. 子查询一般放在条件的最右侧

    3. 标量子查询,一般搭配单行操作符

      <, > , <=, >=, =, !=

    4. 列子查询,一般搭配多行操作符使用

      in, any/some, all

    5. 子查询的执行优先与主查询执行

  1. 标量子查询(单行子查询)

    • 案例1:谁的工资比Abel高

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      SELECT 
      last_name, salary
      FROM
      employees
      WHERE
      salary > (
      SELECT
      salary
      FROM
      employees
      WHERE
      last_name = 'Abel');
    • 案例2:返回job_id与141号员工相同,salary比141号员工多的员工姓名,job_id和工资

      执行单子句查询

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      SELECT 
      last_name, job_id, salary
      FROM
      employees
      WHERE
      job_id = (SELECT
      job_id
      FROM
      employees
      WHERE
      employee_id = 141)
      AND salary > (SELECT
      salary
      FROM
      employees
      WHERE
      employee_id = 143);
    • 案例3:返回公司工资最少的员工的last_name,job_id和salary

      子查询中使用组函数

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      SELECT 
      last_name, job_id, salary
      FROM
      employees
      WHERE
      salary = (SELECT
      MIN(salary)
      FROM
      employees);
    • 案例4:查询最低工资大于50号部门最低工资的部门id和其最低工资

      子句中的HAVING语句

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      SELECT 
      department_id, MIN(salary)
      FROM
      employees
      GROUP BY department_id
      HAVING MIN(salary) > (SELECT
      MIN(salary)
      FROM
      employees
      WHERE
      department_id = 50);
  2. 列子查询(多行子查询)

    • 案例1:返回location_id是1400或1700的部门中的所有员工姓名

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      ## 连接查询
      SELECT
      d.location_id, e.last_name
      FROM
      departments d
      INNER JOIN
      employees e ON e.department_id = d.department_id
      WHERE
      d.location_id IN (1400 , 1700);
      ## 列子查询
      SELECT
      last_name
      FROM
      employees
      WHERE
      department_id IN (SELECT
      department_id
      FROM
      departments
      WHERE
      location_id IN (1400 , 1700));
    • 案例2:返回其他部门中比job_id为’IT_PROG’部门任一工资低的员工的工号,姓名,job_id,以及salary

      在多行子查询中使用ANY操作符

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      SELECT 
      employee_id, last_name, job_id, salary
      FROM
      employees
      WHERE
      salary < ANY (SELECT DISTINCT
      salary
      FROM
      employees
      WHERE
      job_id = 'IT_PROG')
      AND job_id <> 'IT_PROG';
    • 案例3:回其他部门中比job_id为’IT_PROG’部门所有工资低的员工的工号,姓名,job_id,以及salary

      在多行子查询中使用ALL操作符

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      SELECT 
      employee_id, last_name, job_id, salary
      FROM
      employees
      WHERE
      salary < ALL (SELECT
      salary
      FROM
      employees
      WHERE
      job_id = 'IT_PROG')
      AND job_id <> 'IT_PROG';
  3. 行子查询(一行多列,多行多列)

    • 案例:查询员工编号最小的并且是工资最高的员工工号。姓名,工资,job_id

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      SELECT 
      employee_id, last_name, salary, job_id
      FROM
      employees
      WHERE
      employee_id = (SELECT
      MIN(employee_id)
      FROM
      employees)
      AND salary = (SELECT
      MAX(salary)
      FROM
      employees);

二、select语句后面的子查询

select内部仅仅支持标量子查询

  • 案例1:查询每个部门的员工个数

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    ## 子查询
    SELECT
    d.department_id,
    (SELECT
    COUNT(*)
    FROM
    employees e
    WHERE
    e.department_id = d.department_id) COUNT
    FROM
    departments d;
    ## 分组查询
    SELECT
    department_id, COUNT(last_name) COUNT
    FROM
    employees
    GROUP BY department_id;
  • 案例2:查询员工号等于102的部门名

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    ## 子查询版本
    SELECT
    department_name
    FROM
    departments
    WHERE
    department_id = (SELECT
    department_id
    FROM
    employees
    WHERE
    employee_id = 102);
    ## 连接查询
    SELECT
    d.department_name
    FROM
    departments d
    INNER JOIN
    employees e ON e.department_id = d.department_id
    WHERE
    e.employee_id = 102;

三、from后面的子查询

  • 案例1:查询每个部门的平均工资的工资等级

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    SELECT 
    A.department_id, round(A.AVG_SAL, 2), j.grade_level
    FROM
    (SELECT
    AVG(salary) AVG_SAL, department_id
    FROM
    employees
    GROUP BY department_id) A
    INNER JOIN
    job_grades j ON A.AVG_SAL BETWEEN lowest_sal AND highest_sal;

四、exists后面的子查询(相关子查询)

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## 判断子查询里面有没有值
SELECT
EXISTS( SELECT
employee_id
FROM
employees); ## 1
SELECT
EXISTS( SELECT
salary
FROM
employees
WHERE
salary = 30000); ## 0 没有
  • 案例:查询员工的部门名

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    ## exists版本
    SELECT
    department_name
    FROM
    departments d
    WHERE
    EXISTS( SELECT
    *
    FROM
    employees e
    WHERE
    d.department_id = e.department_id);
    ## in版本
    SELECT
    department_name
    FROM
    departments d
    WHERE
    d.department_id IN (SELECT
    department_id
    FROM
    employees e
    WHERE
    e.department_id = d.department_id);

相关测试

  1. 查询和Zlotkey相同部门的员工姓名和工资

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    SELECT 
    last_name, salary
    FROM
    employees
    WHERE
    department_id = (SELECT
    department_id
    FROM
    employees
    WHERE
    last_name = 'Zlotkey');
  2. 查询工资比公司平均工资高得员工的员工号,姓名和工资

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    SELECT 
    employee_id, last_name, salary
    FROM
    employees
    WHERE
    salary > (SELECT
    AVG(salary)
    FROM
    employees);
  3. 查询各部门中工资比本部门平均工资高的员工的员工号和姓名

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    SELECT 
    employee_id, last_name
    FROM
    employees e
    INNER JOIN
    (SELECT
    AVG(salary) av, department_id
    FROM
    employees
    GROUP BY department_id) A ON e.department_id = A.department_id
    WHERE
    e.salary > A.av;
  4. 查询姓名中包含字母u的员工在相同部门的员工的员工号和姓名

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    SELECT 
    employee_id, last_name
    FROM
    employees e
    WHERE
    e.department_id IN (SELECT DISTINCT
    department_id
    FROM
    employees
    WHERE
    last_name LIKE '%u%');
  5. 查询在部门的location_id为1700的部门工作的员工的员工号

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    SELECT 
    employee_id
    FROM
    employees
    WHERE
    department_id IN (SELECT
    department_id
    FROM
    departments
    WHERE
    location_id = 1700);
  6. 查询管理者是K_ing的员工姓名和工资

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    SELECT 
    last_name, salary
    FROM
    employees
    WHERE
    manager_id IN (SELECT
    employee_id
    FROM
    employees
    WHERE
    last_name = 'K_ing');
  7. 查询工资最高的员工姓名,要求first_name和last_name为一列

    ```sql
    SELECT
    CONCAT(first_name, ‘ ‘, last_name)
    FROM
    employees
    WHERE
    salary = (SELECT
    MAX(salary)
    FROM
    employees);